What should have been a peaceful long weekend for one woman and two children instead turned out to be a nightmare for each one of them as they became rape victims.
The first woman was raped on Sunday, May 1 at approximately 02:45 she alleged that she was at her home when her ex-boyfriend came and made a noise outside.
She allowed him into her home as he wanted to speak to her.
He then tried to open her legs even when she told him no, he then forced her to lie on the bed, undressed her, and then raped her.
The suspect is known to her, but he has not been arrested yet.
A 45-year-old woman could not believe what had happened to her two children when she arrived home on Friday, April 29 at 17:40. She alleged that she came home from work and her four children were at home.
She was busy preparing supper, when she went outside and saw her late husband’s friend.
The 45-year-old woman called him over and told him that he could give her a cigarette as usual; he just looked at her and walked away.
That’s when her daughter 10 years old told her that he raped her and her younger sister (six years old).
The older daughter explained to her mother what happened, the suspect called her to come to his house as he had meat for her to take. She then told the suspect that she had meat at home.
It’s alleged that the suspect then convinced the two girls to go over to his house, they went over to his house and he locked the front door. He then told them that they must go straight to his bedroom, then he undressed the six year old and raped her, while doing so he turned up the volume so no one would hear them screaming. After raping her, he raped the older sister.
He then threatened the two girls and told them they must not tell their mother, otherwise he will kill them. Police are busy investigating the case.
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